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4x^2+70x-1200=0
a = 4; b = 70; c = -1200;
Δ = b2-4ac
Δ = 702-4·4·(-1200)
Δ = 24100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24100}=\sqrt{100*241}=\sqrt{100}*\sqrt{241}=10\sqrt{241}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-10\sqrt{241}}{2*4}=\frac{-70-10\sqrt{241}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+10\sqrt{241}}{2*4}=\frac{-70+10\sqrt{241}}{8} $
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